Set path for report viewer in windows service

I have a windows service, which uses quartz to generate reports.

I have set output action of rdlc file to content and copy always. The rdlc file is present in bin/debug folder. When i start windows service. I am getting an error cannot find file "c:\windows\system32\SWKS0057.rdlc". I guess system32 is the folder from which windows service is running. How can i make it to run from the folder where the exe file is present. I can code the path in my program. But i do not know how the production folder will look like.

using (MySqlDataAdapter da = new MySqlDataAdapter(cmd.CommandText, con))
                    {
                        DataTable dt = new DataTable();
                        da.Fill(dt);
                        ReportDataSource rds = new ReportDataSource("DSReportSWKS0057", dt);
                        ReportViewer viewer = new ReportViewer();
                        viewer.ProcessingMode = ProcessingMode.Local;
                        viewer.LocalReport.ReportPath = "SWKS0057.rdlc";
                        //below one works
                        //viewer.LocalReport.ReportPath = @"D:\Shared\windowsservice\bin\Debug\SWKS0057.rdlc";
                        viewer.LocalReport.DataSources.Add(rds);
                        byte[] bytes = viewer.LocalReport.Render("EXCELOPENXML", null, out mimeType, out encoding, out extension, out streamIds, out warnings);
                        FileStream fs = new FileStream(path, FileMode.OpenOrCreate);
                        byte[] data = new byte[fs.Length];
                        fs.Write(bytes, 0, bytes.Length);
                        fs.Close();
                    }